Question

Complete the square to form a true equation;
x^2-3/4x+__ = (x-__)^2

Answer 1

Explanation:

(x^2-3/4x+y^2)=(x-y)2

(x-3/4*1/2)2

(x-3/8)(x-3/8)

(x^2-3x/8-3x/8+9/64)

(x^2-6x/8+9/64)

(x-3/8)2

Answer 2

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