Answer:
0.784 = 78.4% probability that there will be at least one failed graft in the next three done
Explanation:
To solve this question, we need to understand the binomial probability distribution and conditional probability.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: No failed grafts in the first seven
Event B: At least one fail in the next three.
Intersection of events A and B:
Since the probability of a graft failling is independent of other grafts, we have that:

So

So we just have to find the probability of one fail in three trials.
Three trials means that
.
The probability is

In which


Then

0.784 = 78.4% probability that there will be at least one failed graft in the next three done