Answer: B) No; the remainder is 234, so (x+3) is not a factor.
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Step-by-step explanation:
We'll use the remainder theorem. That theorem says if we divide p(x) over (x-k), then the remainder is p(k). A special case of this theorem says that if we get 0 as the remainder, then (x-k) is a factor of p(x).
We're dividing f(x) over (x+3) which means that k = -3. Think of x+3 as x-(-3) so you can match it up with the form x-k.
To find the remainder of f(x)/(x+3), we need to compute f(-3).
Plug x = -3 into the f(x) function to get...
f(x) = 4x^3 + 11x^2 - 75x + 18
f(-3) = 4(-3)^3 + 11(-3)^2 - 75(-3) + 18
f(-3) = 234
The remainder is 234, which is isn't zero, so (x+3) is not a factor of f(x).