Question

What is the completely factored form of this polynomial? x3 + 3x2 - 6x – 18

A. (x - 2)(x - 3)(x + 3)
B. (x2 - 6)(x + 3)
C. (x2 + 3)(x-6)
D. (x + 6)(x - 1)(x + 3)​

Answer 1

(x+3) ( x^2 -6)

Explanation:

x^3 + 3x^2 - 6x – 18

Factor by grouping

x^3 + 3x^2 - 6x – 18

Factor x^2 out of the first group and -6 out of the second group

x^2( x+3) -6(x+3)

Factor out x+3

(x+3) ( x^2 -6)