Answer:
X : ___ 0 ____ 1 _____ 2 _____ 3 _____ 4
P(x): _ 1/16 __ 1/4 ____ 3/8 ____ 1/4 ____ 1/16
Explanation:
Given the listed possible occurrence of boys and girls :
B = boys ; G = girls
BBBB, BBBG, BBGB, BGBB, GBBB, BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, BGGG, GBGG, GGBG, GGGB, and GGGG
Let x = distribution of girls
P = required outcome / Total possible outcomes
For :
x = 0 ;(BBBB) = 1
P(x) = 1/16
x = 1 ; (BBBG, BBGB, BGBB, GBBB) = 4
P(x) = 4 / 16 = 1/4
P(x = 2) ; (BGBG, GBGB, BGGB, GBBG, BBGG, GGBB) = 6
P(x) = 6 / 16 = 3/8
P(x = 3) ; (BGGG, GBGG, GGBG, GGGB) = 4
P(x) = 4 / 16 = 1/4
P(x = 4) ; (GGGG) = 1
P(x) = 1 / 16
X : ___ 0 ____ 1 _____ 2 _____ 3 _____ 4
P(x): _ 1/16 __ 1/4 ____ 3/8 ____ 1/4 ____ 1/16