Question

Find the H.C.F of these expressions.(2a²+6ac,4a²c+12ac²)​

Answer 1

1st expression:2a×a+2×3×a×c

2nd expression:2×2×a×a+2×2×3×a×c×c

here,

2×a×a+2×3×a×c

2a^a+6ac

Answer 2

Hello,

Answer 8a²c(a+3c) =8a³c+24a²c

Explanation:

2a²+6ac=2a(a+3c)

4a²c+12ac²=4ac(a+3c)

H.C.F=2a(a+3c)*4ac=8a²c(a+3c)