Question

SIN TRIG PLEASE HELP 50 POINTS

If sin y° = s/8 and tan y° = s/t what is the value of sec y°
a. sec y° = 8s
b. sec y° = 8t
c. sec y° = 8/t
d. sec y° = t/8

Answer 1

c. sec y° = 8/t

Explanation:

I took the test

Answer 2

C

Explanation:

We are given that:

`\displaystyle \sin y^\circ = (s)/(8)\text{ and } \tan y^\circ = (s)/(t)`

And we want to find the value of:

`\displaystyle \sec y^\circ`

Recall that tan(θ) = sin(θ) / cos(θ). Since sec(θ) = 1 / cos(θ), tan(θ) = sin(θ)sec(θ). Substitute:

`\displaystyle \sin y^\circ \sec y^\circ = (s)/(t)`

Substitute:

`\displaystyle (s)/(8)\sec y^\circ =(s)/(t)`

Solve for secant:

`\displaystyle \sec y^\circ = (8)/(t)`

Hence, our answer is C.