Question

1) Solve ;


`3(x - 5) \leqslant x - 8`

Notes :-

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Answer 1

Hello There!

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`3(x - 5) \leqslant x - 8`

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`\rule{200pt}{5pt}`

Use the distributive property to multiply 3 by x-5

`3x - 15 \leqslant x - 8`

Subtract x from both sides

`3x - 15 - x \leqslant 8`

Combine 2x and -x to get 2x

`2x - 15 \leqslant - 8`

Add 15 to both sides

`2x \leqslant - 8 + 15`

Add -8 and 15 to get 7

`2x \leqslant 7`

Now divide both the sides by 2

As 2 is > 0, the inequality direction remains the same.

`x \leqslant (7)/(2) \\`

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Hope it helps you from my side

:)

Answer 2

x ≤ 7/2

Explanation:

Expand brackets: 3x - 15 ≤ x - 8

Subtract x from both sides: 2x - 15 ≤ -8

Add 15 to both sides: 2x ≤ 7

Divide both sides by 2: x ≤ 7/2