Question

PLEASE HELP- A triangle has vertices A(0, 0), B (9, 4), and C(–2, 10). What are the coordinates of the triangle after a dilation with a scale factor of 1/2 ?

Answer 1

The coordinates of the triangle after a dilation with a scale factor of 1/2 are A'(0, 0), B'(4.5, 2), and C'(-1, 5).

Step-by-step explanation:

To find the coordinates of the triangle after a dilation with a scale factor of 1/2, we need to apply the dilation to each vertex of the triangle.

For vertex A(0, 0), the new coordinates would be (0*(1/2), 0*(1/2)) = (0, 0).

For vertex B(9, 4), the new coordinates would be (9*(1/2), 4*(1/2)) = (4.5, 2).

For vertex C(-2, 10), the new coordinates would be (-2*(1/2), 10*(1/2)) = (-1, 5).

Therefore, the coordinates of the triangle after the dilation are A'(0, 0), B'(4.5, 2), and C'(-1, 5).

Answer 2

Basically multiply the x and y coordinates of each point by 1/2

For example, I'll do C which is ( -2 , 10 )

-2 * 1/2 = -1 and 1/2 * 10 = 5

The new coordinate is ( -1 , 5 )

Now you can try the other points

:D