442,219 views
18 votes
18 votes
Please write down your work on the loose leaf, take a CLEAR picture, and upload here. Thank you.

Please write down your work on the loose leaf, take a CLEAR picture, and upload here-example-1
User Sasank Mukkamala
by
3.0k points

1 Answer

21 votes
21 votes

Answer:

m(∠C) = 18°

Explanation:

From the picture attached,

m(arc BD) = 20°

m(arc DE) = 104°

Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.

m(∠C) =
(1)/(2)[\text{arc(EA)}-\text{arc(BD)}]

Since, AB is a diameter,

m(arc BD) + m(arc DE) + m(arc EA) = 180°

20° + 104° + m(arc EA) = 180°

124° + m(arc EA) = 180°

m(arc EA) = 56°

Therefore, m(∠C) =
(1)/(2)(56^(\circ)-20^(\circ))

m(∠C) = 18°

User Test Team
by
3.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.