Question

You and your friends find a rope that hangs down 11 m from a high tree branch right at the edge of a river. You find that you can run, grab the rope, swing out over the river, and drop into the water. You run at 2.0 m/s and grab the rope, launching yourself out over the river.

Required:
How long must you hang on if you want to drop into the water at the greatest possible distance from the edge?

Answer 1

if you want to drop into the water at the greatest possible distance from the edge, you must hang for 1.662s.

Step-by-step explanation:

The time period of the oscillation is,

`T = 2\pi \sqrt{ \frac{I} {g }`

`T = 2\pi \sqrt{(11)/(9.8) } \\\\T= 6.65 s`

This would be the time taken for the person to move from.

The duration of time he hangs over the river be one-fourth of the time period.

Here,

`t= (T)/(4) \\\\t=(6.65)/(4)\\\\t = 1.662 s`