Question

Calculate the volume in liters of a 0.72 M aluminum sulfate solution that contains 75.0 g of aluminum sulfate Al2SO43.

Answer 1

0.30 L

Step-by-step explanation:

First we convert 75.0 g of Al₂(SO₄)₃ into moles, using its molar mass:

• 75.0 g ÷ 342.15 g/mol = 0.219 mol Al₂(SO₄)₃

Then we can calculate the volume of the solution, by using the definition of molarity:

• Molarity = moles of solute / liters of solution

• 0.72 M = 0.219 mol / Volume

We solve for Volume:

• Volume = 0.30 L