Question

1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.

Answer 1

`n=1.732mol`

`\% N=18.7\%`

Step-by-step explanation:

Hello!

In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

`n=130.0g*(1mol)/(75.07 g)\\\\ n=1.732mol`

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

`\% N=(14.01)/(75.07)*100\% \\\\\% N=18.7\%`

Best regards!