Question

Calculate the volume (in L) that 3.25 mol of helium gas will occupy at a temperature of 25.0 °C and a pressure of 799 mm Hg.

Answer 1

V = 6.34 L

Step-by-step explanation:

Given that,

Number of moles of Helium gas, n = 3.25 mol

Temperature, T = 25 °C = 298 K

Pressure, P = 799 mm Hg

We know that,

PV = nRT

Where

R is the gas constant, R = 62.4 L-mm Hg/mol K

So,

`V=(nRT)/(P)\\\\V=(3.25* 62.4* 25)/(799)\\\\V=6.34\ L`

So, the volume of the gas is 6.34 L.