Question

Two charged particles exert a force of 0.042 N on each other. Suppose that the particles are moved such that they are now one-eighth as far apart. What is the new force between the particles?

Answer 1

New force = 2.688 N

Step-by-step explanation:

Given that,

Two charged particles exert a force of 0.042 N on each other.

Let the initial distance is r. Later the particles are moved such that they are now one-eighth as far apart.

New distance, r' = (r/8)

The force between particles is given by :

`F'=(kq_1q_2)/(r'^2)\\\\F'=(kq_1q_2)/(((r)/(8))^2)\\\\F'=(kq_1q_2)/((r^2)/(64))\\\\F'=64* (kq_1q_2)/(r^2)\\\\F'=64* F\\\\F'=64* 0.042\\\\F'=2.688\ N`

So, the new force is 2.688 N.