Question

A ball is thrown horizontally from the top of a 24.7 m building with a speed of 13.2m/s. Assuming level ground, the ball lands ___ m from the base of the building.

Answer 1

The horizontal distance traveled by the ball is 29.7 m.

Step-by-step explanation:

Given;

height of the building, h = 24.7 m

initial horizontal velocity, Vₓ = 13.2 m/s

The time taken for the ball to fall from the vertical height is calculated as;

`h = V_yt + (1)/(2) gt^2`

where;

`V_y` is initial vertical velocity = 0

`h = 0 + (1)/(2) gt^2\\\\h = (1)/(2) gt^2\\\\t = \sqrt{(2h)/(g) } \\\\t = \sqrt{(2* 24.7)/(9.8) } \\\\t = 2.25 \ s`

The horizontal distance traveled by the ball is calculated as;

`X = V_x t\\\\X = 13.2 *2.25\\\\X = 29.7 m`

Therefore, the horizontal distance traveled by the ball is 29.7 m.