Question

Please help me fast because the due date is tomorrow.​

Answer 1

Explanation:

When the triangles are similar

`(AC)/(PR)=(AB)/(PQ) =(BC)/(QR) \\\\`

Taking First and Third ratios

`(AC)/(PR) =(BC)/(QR) \\\\(8)/(4) =(x)/(3) \\\\x=(8*3)/(4) \\\\x=6cm`

Taking First and Second ratios

`(AC)/(PR) =(AB)/(PQ) \\\\(8)/(4) =(10)/(y) \\\\y=(4*10)/(8)\\\\ y=5cm`

Answer 2

Explanation:

we can find value of x and y through Pythagoras theorem

according to it

h² = a² + b²

h = hypotenuse (i.e longest side of a right angled triangle)

a = side

b = base

in ∆ABC

AB² = AC² + BC²

(10)² = (8)² + x²

100 = 64 + x

x = 100 - 64 = 36

x² = √36 = 6

x = 6

in ∆PQR

PQ² = PR² + RQ²

y² = (4)² + (3)²

y = 16 + 9

y = 25

y² = √25 = 5

y = 5

a) angle BAC = angle QPR

b) value of x = 6 cm

c) value of y = 5 cm

hope this helps you dear!