Can someone please solve 3x^2+4x-7<13

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Xiomy asked Jul 19, 2022

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Can someone please solve 3x^2+4x-7<13

Mathematics
college

Xiomy asked Jul 19, 2022

by Xiomy

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13 votes

Answer:

$-(10)/(3)<x<2\:$

Explanation:

Rewrite in standard form:
3x^2+4x-20<0

Factor:
$\left(x-2\right)\left(3x+10\right)<0$

Solve individually for x:

$x-2<0\\x<2$

$3x+10<0\\3x<-10\\x<(-10)/(3)$

Combine:

$-(10)/(3)<x<2\:$

Sam Zhou answered Jul 26, 2022

by Sam Zhou

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