Question

Glenn shoots an arrow at a 30.0 degree angle. It has a velocity of 65.0 m/s.

How far will the arrow travel? *

Answer 1

The horizontal distance traveled by the projectile is 373.36 m.

Step-by-step explanation:

Given;

angle of projection; θ = 30⁰

initial velocity of the projectile, u = 65 m/s

The horizontal distance traveled by the projectile or range of the projectile is calculated as;

`R = (u^2 * sin(2\theta))/(g) \\\\R = (65^2 * sin(2* 30^0))/(9.8)\\\\R = (4225* sin(60))/(9.8) \\\\R = 373.36 \ m`

Therefore, the horizontal distance traveled by the projectile is 373.36 m.