Question

In ΔJKL, the measure of ∠L=90°, KL = 11 feet, and JK = 32 feet. Find the measure of ∠J to the nearest tenth of a degree.

Answer 1

Answer: J = 20.1

Explanation:

sin J = hypotenuse/opposite = 11/32

Sin J =11/32

J=sin-1(11/32)

J= 20.1055

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