Question

What is the equilibrium expression for the reaction below?

2N,(9)+ 0 (9)
72N0(9)
A.
B.
[NO,
[0][N]
[02] + 2 [N,
2 [NO]
[NO]
[02]+[N]
[02][NZ]
[NO]
C.
D.

Answer 1

A.
`K=([N_2O]^2)/([N_2]^2[O_2])`

Step-by-step explanation:

Hello there!

In this case, for us to figure out the appropriate equilibrium expression, it will be firstly necessary for us to recall the law of conservation of mass which states that the equilibrium constant of an equilibrium chemical reaction is written by dividing the products and reactants and including the stoichiometric coefficients as exponents. In such a way, for the given reaction, we will have:

`K=([N_2O]^2)/([N_2]^2[O_2])`

As N2O is the product whereas N2 and O2 are reactants; thus, the equilibrium expression will be A.

Regards!