Question

1+log2=log(x+1)

I know that x=19 but how do you get 19?

Answer 1

Explanation:

Recall that
`\log 10 = 1` so we can rewrite the equation above as

`\log 10 + \log 2 = \log (x + 1)`

Also recall that
`\log(ab) = \log a + \log b` so the left-hand side becomes

`\log [(10)(2)] = \log (x + 1)`

or

`20 = x + 1 \Rightarrow x = 19`