Question

Determine the moment of inertia of a 14.8 kg sphere of radius 0.752 m when the axis of rotation is through its center.

Answer 1

`I=3.348Kgm^2`

Step-by-step explanation:

From the question we are told that:

Mass
`m=14.8kg`

Radius
`r=0.752m`

Generally the equation for inertia is mathematically given by

`I=(2)/(5)mR^2`

`I=(2)/(5)14.8*(0.752)^2`

`I=3.348Kgm^2`