Question

Katherine Johnson is organizing the sale of supplies for the space mission. On the first day you of sales Dorothy Vaughan purchased 3 blankets and 9 trays for a total of $75. Mary Jackson spent 67 on the second day by purchasing 8 blankets and 5 food trays. What is the price of one blanket ticket and one food tray?

Answer 1

To find the cost of one blanket and one food tray, set up and solve a system of linear equations based on the purchases made on the two days by Dorothy Vaughan and Mary Jackson.

Step-by-step explanation:

The question pertains to solving a system of linear equations with two variables, representing the costs of blankets and food trays. We have two equations based on the given purchases:

• Dorothy Vaughan: 3B + 9T = $75
• Mary Jackson: 8B + 5T = $67

To solve for B (the price of one blanket) and T (the price of one food tray), we can use either substitution or elimination methods. For simplicity, let's use the elimination method:

1. Multiply the first equation by 8 and the second equation by 3 to align the coefficient of B.
2. Subtract the two new equations to eliminate B and solve for T.
3. Substitute T back into one of the original equations to solve for B.

By following these steps, the student will calculate the individual prices for a blanket and a food tray, which represents the solution to this problem.

Answer 2

divide 3 and 75 to get the answer for the blankets, and 9 divide 75. 3 divided 75 is 25; and 9 divide 75 is 8.33$ i think sorry if this is wrong