Question

Calculate the buoyant force due to the surrounding air on a man weighing 600 N . Assume his average density is the same as that of water. Suppose that the density of air is 1.20 kg/m3.

Answer 1

`F_b= 0.720 N`

Step-by-step explanation:

From the question we are told that:

Weight
`W=600N`

Average density
`\rho=1.20kg/m^3`

Mass

`m=(W)/(g)`

`m=(600)/(9.81)`

`m=61.22kg`

Generally the equation for Volume is mathematically given by

`V =( mass)/(density)`

`V= (61.22)/(1000)`

`V=0.06122 m^3`

Therefore

Buoyant force
`F_b`

`F_b=\rho*V*g`

`F_b= rho_air*V*g`

`F_b= 0.720 N`