Question

The product of two consecutive terms of the Arithmetic sequence 5,8,11.....is 598.find the position of the term?

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Answer 1

Explanation:

Common difference is 3.

Let x be a term in the sequence. The next term in the sequence is x+3.

x(x+3) = 598

x² + 3x - 598 = 0

x = [-3 ± √(3²-4⋅1(-598))]/[2⋅1] = [-3 ± 49]/2 = 23, -26

-26 is an extraneous solution, so x = 23.

The two terms are 23 and 26.