Question

Kezang was 5 times as old as his son 10 years ago. After 8 years, Kezang will be twice as

old as his son. What are their present age​

Answer 1

Explanation:

let father's age = x

son's age = y

Five years hence, age of father = x+5

age of son =y+5

So (x+5)= 3(y+5)

⇒x=3y+10

Five years ago, age of father = x-5

age of son = y-5

Sox-5=7(y-5)

⇒3y + 10-5=7y - 35

⇒ 4y = 40

⇒y=10 <<<<<<<
x = 3y +10= 40 <<<<<