Answer:
1 - y + y²
Explanation:
1 + y³ is a sum of cubes and factors in general as
a³ + b³ = (a + b)(a² - ab + b²) , then
1 + y³
= (1 + y)(1² - 1(y) + y²) = (1 + y)(1 - y + y²)
Then
= ← cancel out the common factor (1 + y)
= 1 - y + y²
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