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Describe each polynomial expression by type and components based on the example shown.

3x2 + 2x
2x2 − 5x + 3
6x
Example: -4x2 + 9

This polynomial expression is a quadratic binomial, with a coefficient of -4 on the quadratic term, a constant term of 9, and no linear terms.

User Slayter
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2 Answers

12 votes

Answer:

3x2 + 2x

This polynomial expression is a quadratic binomial, with a coefficient of 3 on the quadratic term, a linear term with coefficient 2, and no constant.

2x2 − 5x + 3

This polynomial expression is a quadratic trinomial, with a coefficient of 2 on the quadratic term, a linear term with coefficient -5, and constant 3.

6x

This polynomial expression is a linear monomial with a coefficient of 6 on the linear term and no constant.

Explanation:

plato answer

User Arnau
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4.6k points
7 votes

Answer:

1)
3\cdot x^(2)+2\cdot x - The polynomial expression is a second-grade binomial, with a coefficient of 3 on the second-grade monomial component and a coefficient of 2 on the first-grade monomial component.

2)
2\cdot x^(2)-5\cdot x + 3 - The polynomial expression is a third-grade trinomial, with a coefficient of 2 on the second-grade monomial component, a coefficient of -5 on the first-grade monomial component and a coeffcient of 3 on the zero-grade monomial component.

3)
6\cdot x - The polynomial expression is a first-grade monomial, with a coefficient of 6 on the first grade monomial component.

Explanation:

1)
3\cdot x^(2)+2\cdot x - The polynomial expression is a second-grade binomial, with a coefficient of 3 on the second-grade monomial component and a coefficient of 2 on the first-grade monomial component.

2)
2\cdot x^(2)-5\cdot x + 3 - The polynomial expression is a third-grade trinomial, with a coefficient of 2 on the second-grade monomial component, a coefficient of -5 on the first-grade monomial component and a coeffcient of 3 on the zero-grade monomial component.

3)
6\cdot x - The polynomial expression is a first-grade monomial, with a coefficient of 6 on the first grade monomial component.

User Peter Kovac
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