Question

PLEASE HELP ASAP, PUT INTO NORMAL NUMBERS, STANDARD FORM?

Answer 1

Given:

The numbers are written in scientific notation.

To find:

The standard form of given numbers.

Solution:

Formula used:

`a^(-n)=(1)/(a^n)`

(a)

`7.2* 10^(-8)=7.2* (1)/(10^8)`

`7.2* 10^(-8)=(7.2)/(1000000000)`

`7.2* 10^(-8)=0.000000072`

(b)

`6.3* 10^(-9)=6.3* (1)/(10^9)`

`6.3* 10^(-9)=(6.3)/(10000000000)`

`6.3* 10^(-9)=0.0000000063`

(c)

`4.54* 10^(-5)=4.54* (1)/(10^5)`

`4.54* 10^(-5)=(4.54)/(100000)`

`4.54* 10^(-5)=0.0000454`

(d)

`7.041* 10^(-10)=7.041* (1)/(10^(10))`

`7.041* 10^(-10)=(7.041)/(100000000000)`

`7.041* 10^(-10)=0.0000000007041`

Therefore,
`7.2* 10^(-8)=0.000000072, 6.3* 10^(-9)=0.0000000063, 4.54* 10^(-5)=0.0000454,`

`7.041* 10^(-10)=0.0000000007041`.