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31 votes
How do you calculate 6^2 +(17-4) -3(7+5) x √16

User Pkberlin
by
2.9k points

2 Answers

21 votes
21 votes

Answer:

= -216x + 49

Explanation:

Apply rule √1 =1

= 6^2 + 17 - 4 - 3 . 1 . 6 (7 + 5)x

3(7 + 5)x . 1 . 6 = 216

= 6^2 + 17 - 4 - 216

Add/Subtract the numbers: 17 - 4 = 13

= -216 + 6^2 + 13

6^2 = 36

= -216x + 6^2 + 13

Add the numbers: 36 + 13 = 49

= -216x + 49

User Abhishek Kulkarni
by
3.1k points
18 votes
18 votes

Answer: -95

Explanation:

Concept:

When you got stuck with doing calculations, it is suggested to follow the PEMDAS method which will ease the process.

  • Parenthesis
  • Exponents
  • Multiplication
  • Division
  • Addition
  • Subtraction

-------------------------------------------------------------

Solve:

6² + (17-4) - 3(7+5) × √16 ⇒ Given

=6² + 13 - 3(12) ×√16 ⇒ Parenthesis

=36 + 13 - 3(12) × 4 ⇒ Exponents

=36 + 13 - 36 × 4 ⇒ Multiplication

=36 + 13 - 144 ⇒ Multiplication

=49 - 144 ⇒ Addition

=-96 ⇒ Subtraction

Hope this helps!! :)

Please let me know if you have any questions

User Hugo Vares
by
2.8k points