Question

Solve. -7x+1-10x^2=0

Answer 1

`-7x+1-10x^2=0`

`-10x^2-7x+1=0`

`quadratic\:equation:-`
`ax^2+bx+c=0`

`solutions:-\\\\x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)`

`For \\A=-10\\B=-7\\C=1`

`x_(1,\:2)=(-\left(-7\right)\pm √(\left(-7\right)^2-4\left(-10\right)\cdot \:1))/(2\left(-10\right))`

`√(\left(-7\right)^2-4\left(-10\right)\cdot \:1)=√(89)`

`x_(1,\:2)=(-\left(-7\right)\pm √(89))/(2\left(-10\right))`

`x_1=(-\left(-7\right)+√(89))/(2\left(-10\right)),\:x_2=(-\left(-7\right)-√(89))/(2\left(-10\right))`

`(-\left(-7\right)+√(89))/(2\left(-10\right))=-(7+√(89))/(20)`

`(-\left(-7\right)-√(89))/(2\left(-10\right))=(√(89)-7)/(20)`

`x=(√(89)-7)/(20)`

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