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Solve. -7x+1-10x^2=0

User Ipj
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1 Answer

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20 votes

Answer:


-7x+1-10x^2=0


-10x^2-7x+1=0


quadratic\:equation:-
ax^2+bx+c=0


solutions:-\\\\x_(1,\:2)=(-b\pm √(b^2-4ac))/(2a)


For \\A=-10\\B=-7\\C=1


x_(1,\:2)=(-\left(-7\right)\pm √(\left(-7\right)^2-4\left(-10\right)\cdot \:1))/(2\left(-10\right))


√(\left(-7\right)^2-4\left(-10\right)\cdot \:1)=√(89)


x_(1,\:2)=(-\left(-7\right)\pm √(89))/(2\left(-10\right))


x_1=(-\left(-7\right)+√(89))/(2\left(-10\right)),\:x_2=(-\left(-7\right)-√(89))/(2\left(-10\right))


(-\left(-7\right)+√(89))/(2\left(-10\right))=-(7+√(89))/(20)


(-\left(-7\right)-√(89))/(2\left(-10\right))=(√(89)-7)/(20)


x=(√(89)-7)/(20)

OAmalOHopeO

User Gustavo Sanchez
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