Question

Find the mass of Mg required to react with 5.00 g of HCl and produce MgCl2 and H2 using the following equation:

Mg(s) + 2HCl(aq) → MgCl2(aq) +H2(g)

Answer 1

1.64 g of Mg

Step-by-step explanation:

The balanced equation for the reaction is given below:

Mg + 2HCl —> MgCl₂ + H₂

Next, we shall determine the masses of Mg and HCl that reacted from the balanced equation. This can be obtained as follow:

Molar mass of Mg = 24 g/mol

Mass of Mg from the balanced equation = 1 × 24 = 24 g

Molar mass of HCl = 1 +35.5

= 36.5 g/mol

Mass of HCl from the balanced equation = 2 × 36.5 = 73 g

SUMMARY:

From the balanced equation above,

24 g of Mg reacted with 73 g of HCl.

Finally, we shall determine the mass of Mg required to react with 5 g of HCl. This can be obtained as illustrated below:

From the balanced equation above,

24 g of Mg reacted with 73 g of HCl.

Therefore, Xg of Mg will react with 5 g of HCl i.e

Xg of Mg = (24 × 5)/ 73

Xg of Mg = 1.64 g

Thus, 1.64 g of Mg is required for the reaction.