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Factorise (x+y)^3- (x^3+y^3) plzzz answer ​

User Almendar
by
7.0k points

1 Answer

6 votes

Answer:


\huge \boxed{ \boxed{ \tt 2xy(x + y)}}

Explanation:

to understand this

you need to know about:

  • factoring
  • PEMDAS

tips and formulas:

  • (a+b)³=a³+3a²b+3ab²+b³
  • a³+b³=(a+b)(a²-ab+b²)

let's solve:


  1. \sf \: use \: 2nd \: formula \: to \: simplify : \\ \sf(x + y {)}^(3) - (x + y)( {x}^(2) - xy + {y}^(2) )

  2. \sf factor \: out \: (x + y) : \\ (x + y )\{(x + y)^(2) - ( {x}^(2) - xy + {y}^(2) \}

  3. \sf simplify : \\ (x + y {)} \{ {x}^(2) + 2xy + {y}^(2) - {x}^(2) + xy - {y}^(2) \}

  4. \sf collect \: and \: combine \: like \: terms : \\ (x + y) \{2xy \}

  5. \sf \: rewrite : \\ 2xy(x + y)

and

we are done

User Andor Kesselman
by
7.9k points