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Find the equation of the line that contains the given point and with the given slope. Write the equation in slope-intercept form, if possible, and graph the line (2,1); slope =3

User Athanatos
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\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the straight lines.

y-y1 = m(x-x1) + C

====> y - 1 = 3(x - 2)

====> y-1 = 3x -6

====> y = 3x - 5

hence the equation is y = 3x - 5

User Robert Waddell
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