Answer: The answer is letter A. 0.1s...... I think
-16t^2 + 50t + 3.5= 0
Step-by-step explanation: The answer is either letter A or letter B
Question
Use the vertical motion formula h=-16 t^{2}+v t+ch=−16t
2
+vt+c. A soccer ball is kicked with a starting upward velocity of 50 ft/s from a starting height of 3.5 ft. Substitute the values into the vertical motion formula Let h = 0.
Explanation
Step 1
1 of 2
The starting velocity is 50 ft/s ,when the ball is 3.5 ft high
So, v=50v=50 , h=3.5h=3.5 , t=0t=0
\begin{align*} h&=-16t^2+vt+c &&\text{{\color{#c34632}The vertical motion formula}}\\\\ 3.5&=-16(0)^2+50(0)+c &&\text{{\color{#c34632}Substitute 3.5 for $h$ , 50 for $v$ , 0 for $t$}}\\\\ c&=3.5 &&\text{{\color{#c34632}Simplify}}\\\\ \end{align*}
h
3.5
c
=−16t
2
+vt+c
=−16(0)
2
+50(0)+c
=3.5
The vertical motion formula
Substitute 3.5 for h , 50 for v , 0 for t
Simplify
So, the vertical motion formula will be
h= -16t^2 + 50t + 3.5
Let h= 0
-16t^2 + 50t + 3.5= 0