Answer:
27.99 g of CsF
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CsF + XeF₆ —> CsXeF₇
Next, we shall determine the mass of CsF that reacted and the mass of CsXeF₇ produced from the balanced equation. This can be obtained as follow:
Molar mass of CsF = 133 + 19
= 152 g/mol
Mass of CsF from the balanced equation = 1 × 152 = 152 g
Molar mass of CsXeF₇ = 133 + 131 + (19× 7)
= 133 + 131 + 133
= 397 g/mol
Mass of CsXeF₇ from the balanced equation = 1 × 397 = 397 g
SUMMARY:
From the balanced equation above,
152 g of CsF reacted to produce 397 g of CsXeF₇.
Finally, we shall determine the mass of CsF required to produce 73.1 g of CsXeF₇. This can be obtained as follow:
From the balanced equation above,
152 g of CsF reacted to produce 397 g of CsXeF₇.
Therefore, Xg of CsF will react to produce 73.1 g of CsXeF₇ i.e
Xg of CsF = (152 × 73.1)/397
Xg of CsF = 27.99 g
Thus, 27.99 g of CsF is required for the reaction.