Answer:
A) L = 0.388 μm
B) D = 3.78 mm
Step-by-step explanation:
We are given;
Characteristics impedance; Z_o = 75 ohms
Nominal capacitance; C = 69pF/m = 69 × 10^(-12) F/m
dielectric constant; k = 2.23
Inner diameter of conductor; d = 0.584 mm
A) Now formula for Characteristics impedance is given as;
Z_o = √(L/C)
Where L is the inductance per metre.
Making L the subject, we have;
L = (Z_o)²C
L = 75² × 69 × 10^(-12)
L = 0.388 × 10^(-6) m
L = 0.388 μm
B) To get the outer diameter, we will use the formula;
Z_o = (138/√k) log(D/d)
Where;
D is outer diameter.
Thus, Plugging in the relevant values;
75 = (138/√2.23) × log (D/0.584)
log (D/0.584) = 0.81158611538
(D/0.584) = 10^(0.81158611538)
D/0.584 = 6.48016576435
D = 6.48016576435 × 0.584
D = 3.78 mm