( {3 x}^(2) - 4x + 8) + ( - {x}^(2) - 2x - 8) a. {2x}^(2) - 6 b. {2x}^(2) - 2x c. {2x}^(2) - 6x + 1 d. {2x}^(2) + 6

asked Apr 9, 2022 202k views

25 votes

$( {3 x}^(2) - 4x + 8) + ( - {x}^(2) - 2x - 8)$

a.

${2x}^(2) - 6$
b.

${2x}^(2) - 2x$
c.

${2x}^(2) - 6x + 1$
d.

${2x}^(2) + 6$

by Pbuck

5.6k points

Please log in or register to add a comment.

4 votes

Answer:

A. 2x^2 - 6x

Explanation:

Tropin Alexey answered Apr 14, 2022

5.9k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.0m questions

7.8m answers