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( {3 x}^(2) - 4x + 8) + ( - {x}^(2) - 2x - 8) a. {2x}^(2) - 6 b. {2x}^(2) - 2x c. {2x}^(2) - 6x + 1 d. {2x}^(2) + 6 ​
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( {3 x}^(2) - 4x + 8) + ( - {x}^(2) - 2x - 8)

a.

{2x}^(2) - 6
b.

{2x}^(2) - 2x
c.

{2x}^(2) - 6x + 1
d.

{2x}^(2) + 6
​

User Pbuck
by
8.9k points

1 Answer

4 votes

Answer:

A. 2x^2 - 6x

Explanation:

User Tropin Alexey
by
8.3k points
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