Question

Find a33 of the arithmetic sequence given a1=17 and d=6.

Answer 1

209

Explanation:

Given the following:

`a_(1) = 17\\d=6`

The nth term of an arithmetic sequence is expressed as:

`a +(n-1)d`

a is the first term = 17

d is the common difference =6

Get the 33rd term:

`n=33\\a_(33)=17+(33-1)*6\\a_(33) =17+32(6)\\a_(33)=17+192\\a_(33)=209`

Hence the 33rd term is 209