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Let f(x) = 2x –1 and g(x) = x2+ x –3. Which equation shows h(x), where h(x) = f(x) ∙g(x)?

A) h(x) = x2+ x + 3
B) h(x) = -x2+ 3x –4
C) h(x) = -2x3+ x2–5x –3
D) h(x) = 2x3+ x2–7x + 3

User Pegues
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2 Answers

7 votes
The answer is:D
Choice D
User Andy Ross
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9 votes

Answer:

D) h(x) = 2x³ +x² -7x +3

Explanation:

The product of the two functions is ...

h(x) = f(x)·g(x)

h(x) = (2x -1)(x² +x -3) = 2x(x² +x -3) -1(x² +x -3)

h(x) = 2x³ +2x² -6x -x² -x +3

h(x) = 2x³ +x² -7x +3 . . . . . . matches choice D

User Julz
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