Question

1. Determine the magnitude of two equal but opposite charges if they attract one another with a force of 0.7N when at distance of 0.3m apart in a vacuum.​

Answer 1

q = 2.65 10⁻⁶ C

Step-by-step explanation:

For this exercise we use Coulomb's law

F =
`k (q_1q_2)/(r^2)`

In this case they indicate that the load is of equal magnitude

q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

F =
`k \ (q^2)/(r^2)`

q =
`\sqrt{(F \ r^2)/(k) }`

we calculate

q =
`\sqrt{(0.7 \ 0.3^2 )/(9 \ 10^9) }`

q =
`\sqrt{7 \ 10^(-12) }`Ra 7 10-12

q = 2.65 10⁻⁶ C