Answer:
2721.02 g
Step-by-step explanation:
you need the molar mass of the compound to solve this
S2O6's molar mass: 2(S) + 6(O)
Sulfur (S) molar mass: 32.06
Oxygen (O) molar mass: 15.99
2(32.06) + 6(15.99) --> 64.12 + 95.94 = 160.06 g/mol
We want to know how much of it is in 17.7 moles, so you perform the following stoichiometry
160.06 g/mol * 17.7 mol
mol units cancel out and we are left with g.
160.06 * 17.7 = 2721.02 g of S2O6 in 17.7 moles of it