Question

Please help me solve this

a waitress sold 17 ribeye steak dinners and 10 grilled salmon dinners, totaling $580.22 on a particular day. Another day she sold 21 ribeye steak dinners and 5 grilled salmon dinners, totaling $582.19 how much did each type of dinner cost.

Answer 1

`each \: ribeye \: costs \: \boxed{(r) \to \: \$23.3664} ......................... .. \\ each \: grilled \: salmon \: dinners \: costs \: \boxed{(r) \to \: \$18.29912}`

Explanation:

`let \: ribeye \: be \to \: (r).......................... \\ let \: grilled \: salmon \: dinners \: be \to \: (g) \\ \tt{hence} \to\\ (5) * 17r + 10g = \$580.22 \\(10) * 21r + 5g = \$582.19 \\ \to \\ (85r + 50g = 2,901.1) \\ - (minus)\\ (210r + 50g =5,821.9 ) \\ - 125r = - 2,920.8 \\ r = ( -2,920.8 )/( - 125) \\ \boxed{r = \$23.3664} \\ \tt{hence} \to\\17r + 10g = \$580.22 \\ 17(23.3664) + 10g = \$580.22 \\1 0g = \$580.22 - \$397.2288 \\ 10g = \$182.9912 \\ g = (\$182.9912)/(10) \\ \boxed{g = \$18.29912}`