Answer:
2(CaSO4)*H2O
Step-by-step explanation:
To solve this question we need to find the moles water, H2O, of calcium sulfate, CaSO4 as follows:
The molar mass of the anhydrous CaSO4 are 136.14g/mol and the molar mass of the hemihydrate is 145.15g/mol. The differences in molar mass represents the additional mass that water is producing:
145.15g/mol - 136.14g/mol = 9.01g/mol
A 1 mole of water weighs 18.015g/mol, the additional mass of water is due the addition of 1/2 moles of H2O. That means we have 1 mole of CaSO4 per 1/2 mole of H2O. That is the same:
2(CaSO4)*H2O
And this is the formula that gives the correct ratio for the hemihydrate.