Question

If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizontal, calculate the final position made with the vertical (Yf) after 1.3 seconds.

Answer 1

The final position made with the vertical is 2.77 m.

Step-by-step explanation:

Given;

initial velocity of the ball, V = 17 m/s

angle of projection, θ = 30⁰

time of motion, t = 1.3 s

The vertical component of the velocity is calculated as;

`V_y = Vsin \theta\\\\V_y = 17 * sin(30)\\\\V_y = 8.5 \ m/s`

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

`Y_f = V_yt - (1)/(2)g t^2\\\\Y_f = (8.5 * 1.3 ) - ((1)/(2) * 9.8 * 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m`

Therefore, the final position made with the vertical is 2.77 m.