Question

A triangle has two sides measuring 10 inches and 16 inches. The angle opposite the 16-inch side measures 68.9°. Solve the triangle. Round answers to the nearest tenth of a degree. Do not round intermediate values.

Answer 1

measure of two unknown angles are 35.7° and 75.4°

measure of one unknown side is 16.6 inches

Explanation:

i used law of sines to find the angle opposite 10 inch side

sin 68.9/16 = sinФ/10

Ф = 35.7°

then is added 35.7 and 68.9 and subtracted the sum from 180° to get the measure of the third angle, 75.4°

i used law of sines again to find the measure of the third side

sin 68.9/16 = sin 75.4/x

x = 16.59