Answer:
see below
Explanation:
If two lines are perpendicular to each other, they have opposite slopes.
The first line is y = 6/7x. Its slope is (6/7). A line perpendicular to this one will have a slope of -7/6.
Plug this value (-7/6) into your standard point-slope equation of y = mx + b.
y = -7/6x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (6, 3). Plug in the x and y values into the x and y of the standard equation.
3 = -7/6(6) + b
To find b, multiply the slope and the input of x (6)
3 = -42/6 + b
3 = -7 + b
Now, add 7 to both sides to isolate b.
10 = b
Plug this into your standard equation.
y = -7/6x + 10
This equation is perpendicular to your given equation (y = 6/7x -7) and contains point (6, 3)
If two lines are parallel to each other, they have the same slope.
The first line is y = 6/7x - 7. Its slope is (6/7). A line parallel to this one will also have a slope of 6/7.
Plug this value (6/7) into your standard point-slope equation of y = mx + b.
y = 6/7x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (6, 3). Plug in the x and y values into the x and y of the standard equation.
3 = 6/7(6) + b
To find b, multiply the slope and the input of x (6)
3 = 36/7 + b
Now, subtract 36/7 to both sides to isolate b. To make this easier to visualize, convert 3 to have a denominator of 7.
21/7 - 36/7 = b
-15/7 = b
Plug this into your standard equation.
y = 6/7x - 15/7
This equation is parallel to your given equation (y = 6/7x - 7) and contains point (6, 3)
Hope this helps!