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What is the oxidation number of s in na2s4o6?

User Fpes
by
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2 Answers

3 votes

Answer:

+2.5

Step-by-step explanation:

So the oxidation number of S in Na2S4O6is +2.5.

User Travis Reeder
by
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4 votes

Answer:

Step-by-step explanation:

Oxidation number of Na = 1+ There are two of them, so it is 2*1 = 2

Oxidation number of O = 2- There are 6 of them so 6 * 2- = -12

There are 4 S's so the oxidation number is 4*S

Now set up a small equation

2 + 4s - 12 = 0

And solve.

2 - 12 + 4s =0

-10 + 4s = 0

4s = 10

4s/4 =10/4

s = 2.5

User Saddie
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4.7k points